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-5x^2+3x+110=0
a = -5; b = 3; c = +110;
Δ = b2-4ac
Δ = 32-4·(-5)·110
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-47}{2*-5}=\frac{-50}{-10} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+47}{2*-5}=\frac{44}{-10} =-4+2/5 $
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